Algebra 1 homework, math homework help

Easy, Algebra 1 homework. Has to be done perfectly. You can fill in the answers with explanations on the edible pdf file, if needed I have a word document that can be used as well. There are pages from a textbook that need to be used and i will attach them in the order per questions. And you can read the page numbers on the bottom right corner of the pages.

58
every positive
Anciano
nC ni ab
(a+b)= nCoat
Activity
Lab
Linear
Programming
Technology
FOR USE WITH LESSON 3-4
Go
You can solve linear programming problems with your graphing calculator.
nline
PHSchool.com
For: Graphing calculator
ACTIVITY
procedures
Web Code: age-2109
Find the values of x and y that will maximize the objective function
P = 13x + 2y for the constraints at the right. What is the value of P
at this maximum point?
– 3x + 2ys 8
-8x + y = -48
x = 0, y = 0
Step 1 Rewrite the first
two inequalities to isolate
y. Enter the inequalities.
Step 2 Graph, using the
window 0 < x < 12, 0 y s 20. Step 3 Use the value option of CALC to find the upper left vertex. Press 0 ENTER Y1=(3/2)X +4 Plot1 Plot2 Plot3 Y1 = (3/2)X+4 VY2 E 8X-48 Y3 = Y4= Y5= SY6 = \Y7 = X=0 Step 4 Enter the expression for the objective function on the home screen. Press ENTER for the value of P at the vertex. Step 5 Use the intersect option of CALC to find the upper right vertex. Go to the home screen and press ENTER for the value of P. Step 6 Use the zero option of CALC to find the lower right vertex. Go to the home screen and press ENTER for the value of P. 13X+2Y 13X+2Y 8 8 136 78 Intersection: X=8 Y=161 Compare the values of P for the coordinates of the three vertices you found. . The objective function has a value of 0 for the vertex located at the origin. The maximum value 136 occurs when x = 8 and y y = 16. EXERCISES Find the values of x and y that maximize or minimize the objective function. * (3x + 5y = 35 2. 2x + y = 14 x 20, y 2 0 4x + 3y = 30 x + 3y 2 21 x = 0, y 20 x + y 28 3.x + 5y = 20 (x = 0, y = 2 4. x + 2y = 24 3x + 2y = 34 3x + y = 29 x 20 1. Minimum for C = 5x + 8y Maximum for P = 3x + 2y Minimum for C = 3x + 4y Maximum for P = 2x + 3y Activity Lab Linear Programming Linear Programming 145 DK Activity Lab Tbos besibus Building a Business Applying Inequalities The efficiency of a factory depends on how you divide limited resources among the products produced. The bad news is that in any factory you have a limited number of machines and raw materials available. The good news is that these limitations lead to inequalities that you can use to decide how to maximize your profits. 3 The inside of the cocoa bean is ground into a The cacao tree grows 1 in tropical jungles. It produces melonlike fruits, each containing 20-40 cocoa beans. concentrated chocolate liquid. 2 After roasting, cocoa beans pass through a machine that separates the shell from the inside of the bean. Activity You are in charge of a small private chocolate factory that makes two popular and profitable chocolate bars, Cocoa Bar and Choco-Lot. Your goal is to figure out how many of each type of chocolate bar you should produce each day to maximize your company's profits. Here are a few key pieces of information: • The success of your chocolate recipes lies Flavor A Flavor B in your use of two secret ingredients, Production rate 126 kg/day 136 kg/day referred to as Flavor A and Flavor B to protect the company's interests. The table Cocoa Bar requirements 1.8 g/bar 4.0 g/bar shows the production rate and Choco-Lot requirements 2.8 g/bar 1.7 g/bar requirements of the flavors. • One machine wraps both candy bars. It can wrap 50,000 chocolate bars per day. • Your profit on each Cocoa Bar bar is 14¢, and your profit on each Choco-Lot bar is 12¢. a. Write inequalities to describe each objective and constraint. b. Graph the inequalities you wrote in part (a). c. Find the quantity of each chocolate bar you should manufacture to maximize your daily profit. Calculate the profit you will earn. 4 All photographs © Dorling Kindersley Limited into Chocolate Fondue To make chocolate fondue, melt chocolate gently over low heat. Dip pieces of fruit in the melted chocolate. Milk and sugar are mixed 4 together before being added to the cocoa bean liquid. Any gritty particles are removed by machine. v 7 The chocolate paste is ready to be cooled and molded. 5 5 The cocoa, milk, and sugar mixture is dried to a powder and mixed with cocoa butter to make a chocolate paste. White Chocolate White chocolate is not a real chocolate, since it does not contain cocoa solids. A good white chocolate is made with cocoa butter as well as milk solids and sugar. 8 The molded chocolate takes a bumpy ride along a conveyor belt to eliminate air bubbles as it cools. It's ready for wrapping! Go Online PHSchool.com For: Information about manufacturing Web Code: age-0453 2 Activity Lab Quadratic Inequalities FOR USE WITH LESSON 5-8 Technology You can solve quadratic inequalities using graphs, tables, and algebraic methods. Indeed, the most effective way may be a combination of methods. ACTIVITY To find which of x2 - 12 or 3x + 6 is greater, enter the two functions as Yi and Y2 in your graphing calculator, you could use the TABLE option to compare the two functions for various values of x, as shown below. Y2 Plot1 Plot2 Plot3 Y1 = x2- 12 Y2 E 3X + 6 Y3 = Y4 = Y5 = \ Y6 = \Y7= TABLE SETUP TblStart=-10 ATbl=5 Indpnt: AUTO ASK Depend: AUTO ASK Х -10 -5 0 5 10 15 20 X=-10 Y1 88 13 -12 13 88 213 388 -9 6 21 36 Noonmin 66 1. For which values of x in the table is x2 - 12 > 3x + 6?
2. For which values of x in the table is x2 – 12 < 3x + 6? 3. Does this table tell you all values of x for which x2 - 12 < 3x + 6? Explain. 4. In the TBLSET (TABLE SETUP) menu, change TbiStart to -9 and ATbl to 3. Display the table again. Does the table with this setup give you more information? Why? Х -9 -6 -3 You can compare functions more efficiently by making one side of the inequality 0. 5. Show that x2 - 12 < 3x + 6 is equivalent to x2 – 3x – 18 < 0. 6. Enter x2 – 3x – 18 as Yz in your graphing calculator. Place the cursor on the = sign after Y1 and press ENTER. This operation turns off the display of the equation Y1. Turn off Y2 as well, and then display the table. You will see the screen shown at the right. For which values of x in the table is x2 – 3x – 18