MATH 20TEST 3

Write your number in the box above.

Due:

Tuesday, 7-28-2020, 11:59 p.m.

Name

(Show necessary work.)

(1)

Let

P (x) = 2×2 − 3x + 7;

(a)

Find P (−5)

(1a)

(b)

Find P (3a − 2)

(1b)

2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =

(2)

Simplifying:

(3)

Multiply:

(4)

Expanding and simplifying:

(4×2 − 5x + 1)(3×2 − 2x − 4) =

(x + 5y)2 − (5x − 3y)2 =

(2)

(3)

(4)

(5)

Factor:

3×5 − 48x =

(5)

(6)

Factor:

5×3 − 20×2 − 105x =

(6)

(7)

Factor:

4×3 − x2 − 36x + 9 =

(7)

(8)

Factor:

27×3 − 64y 3 =

(8)

(9)

Solve for x:

2x(x − 7)(4x + 5)(5x − 8) = 0

(9)

(10)

6×2 + 5x − 4 = 0

Solve for x:

Rewriting:

p

(a) write 7 5×2 y 5 in power notation.

(10)

(11)

3

(b) write (8x) 4 in radical notation.

2

(12)

Simplifying:

(27a12 b15 ) 3 =

(13)

Simplifying:

( 36

)− 2 =

49

(14)

Simplifying:

(15)

Expanding:

1

√

4

(11b)

(12)

(13)

32a31 b18 c4 =

1

(11a)

1

(2x 2 − 5y 2 )2 =

(14)

(15)

√

√

√

7 4 81 − 3 3 64 + 5 3 27 =

(16)

Simplifying:

(17)

Rationalizing the denominator:

(18)

Solve:

(19)

Find the following powers:

√

√ 6√

5+ 2

(16)

=

(17)

8−x=x−2

(18)

(a) i310 =

(19a)

(b) (i12 )2 · i87 =

(19b)

(20)

(a)

Rewrite the following imaginary numbers, using i:

√

−49 =

(b)

√

−180 =

(21)

(−11 + 7i) − (−5i + 4) + (9 − 15i) =

(21)

(22)

2i(5 + 3i)(7 − 9i) =

(22)

(23)

(9 − 5i)2 =

(23)

(24)

3+2i

4−3i

(24)

(25)

2

( i−2

3+i ) =

=

(25)

Math20

Test 3,

100 points

MATH 20

TEST 3

Write your number in the box above.

Due:

Tuesday, 7-28-2020, 11:59 p.m.

Name

(Show necessary work.)

(1)

Let

P (x) = 2×2 − 3x + 7;

(a)

Find P (−5)

(1a)

(b)

Find P (3a − 2)

(1b)

2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =

(2)

Simplifying:

(3)

Multiply:

(4)

Expanding and simplifying:

(4×2 − 5x + 1)(3×2 − 2x − 4) =

(x + 5y)2 − (5x − 3y)2 =

(2)

(3)

(4)

(5)

Factor:

3×5 − 48x =

(5)

(6)

Factor:

5×3 − 20×2 − 105x =

(6)

(7)

Factor:

4×3 − x2 − 36x + 9 =

(7)

(8)

Factor:

27×3 − 64y 3 =

(8)

(9)

Solve for x:

2x(x − 7)(4x + 5)(5x − 8) = 0

(9)

(10)

6×2 + 5x − 4 = 0

Solve for x:

Rewriting:

p

(a) write 7 5×2 y 5 in power notation.

(10)

(11)

3

(b) write (8x) 4 in radical notation.

2

(12)

Simplifying:

(27a12 b15 ) 3 =

(13)

Simplifying:

( 36

)− 2 =

49

(14)

Simplifying:

(15)

Expanding:

1

√

4

(11b)

(12)

(13)

32a31 b18 c4 =

1

(11a)

1

(2x 2 − 5y 2 )2 =

(14)

(15)

√

√

√

7 4 81 − 3 3 64 + 5 3 27 =

(16)

Simplifying:

(17)

Rationalizing the denominator:

(18)

Solve:

(19)

Find the following powers:

√

√ 6√

5+ 2

(16)

=

(17)

8−x=x−2

(18)

(a) i310 =

(19a)

(b) (i12 )2 · i87 =

(19b)

(20)

(a)

Rewrite the following imaginary numbers, using i:

√

−49 =

(b)

√

−180 =

(21)

(−11 + 7i) − (−5i + 4) + (9 − 15i) =

(21)

(22)

2i(5 + 3i)(7 − 9i) =

(22)

(23)

(9 − 5i)2 =

(23)

(24)

3+2i

4−3i

(24)

(25)

2

( i−2

3+i ) =

=

(25)

Math20

Test 3,

100 points

MATH 20

TEST 3

Write your number in the box above.

Due:

Tuesday, 7-28-2020, 11:59 p.m.

Name

(Show necessary work.)

(1)

Let

P (x) = 2×2 − 3x + 7;

(a)

Find P (−5)

(1a)

(b)

Find P (3a − 2)

(1b)

2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =

(2)

Simplifying:

(3)

Multiply:

(4)

Expanding and simplifying:

(4×2 − 5x + 1)(3×2 − 2x − 4) =

(x + 5y)2 − (5x − 3y)2 =

(2)

(3)

(4)

(5)

Factor:

3×5 − 48x =

(5)

(6)

Factor:

5×3 − 20×2 − 105x =

(6)

(7)

Factor:

4×3 − x2 − 36x + 9 =

(7)

(8)

Factor:

27×3 − 64y 3 =

(8)

(9)

Solve for x:

2x(x − 7)(4x + 5)(5x − 8) = 0

(9)

(10)

6×2 + 5x − 4 = 0

Solve for x:

Rewriting:

p

(a) write 7 5×2 y 5 in power notation.

(10)

(11)

3

(b) write (8x) 4 in radical notation.

2

(12)

Simplifying:

(27a12 b15 ) 3 =

(13)

Simplifying:

( 36

)− 2 =

49

(14)

Simplifying:

(15)

Expanding:

1

√

4

(11b)

(12)

(13)

32a31 b18 c4 =

1

(11a)

1

(2x 2 − 5y 2 )2 =

(14)

(15)

√

√

√

7 4 81 − 3 3 64 + 5 3 27 =

(16)

Simplifying:

(17)

Rationalizing the denominator:

(18)

Solve:

(19)

Find the following powers:

√

√ 6√

5+ 2

(16)

=

(17)

8−x=x−2

(18)

(a) i310 =

(19a)

(b) (i12 )2 · i87 =

(19b)

(20)

(a)

Rewrite the following imaginary numbers, using i:

√

−49 =

(b)

√

−180 =

(21)

(−11 + 7i) − (−5i + 4) + (9 − 15i) =

(21)

(22)

2i(5 + 3i)(7 − 9i) =

(22)

(23)

(9 − 5i)2 =

(23)

(24)

3+2i

4−3i

(24)

(25)

2

( i−2

3+i ) =

=

(25)

Math20

Test 3,

100 points

MATH 20

TEST 3

Write your number in the box above.

Due:

Tuesday, 7-28-2020, 11:59 p.m.

Name

(Show necessary work.)

(1)

Let

P (x) = 2×2 − 3x + 7;

(a)

Find P (−5)

(1a)

(b)

Find P (3a − 2)

(1b)

2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =

(2)

Simplifying:

(3)

Multiply:

(4)

Expanding and simplifying:

(4×2 − 5x + 1)(3×2 − 2x − 4) =

(x + 5y)2 − (5x − 3y)2 =

(2)

(3)

(4)

(5)

Factor:

3×5 − 48x =

(5)

(6)

Factor:

5×3 − 20×2 − 105x =

(6)

(7)

Factor:

4×3 − x2 − 36x + 9 =

(7)

(8)

Factor:

27×3 − 64y 3 =

(8)

(9)

Solve for x:

2x(x − 7)(4x + 5)(5x − 8) = 0

(9)

(10)

6×2 + 5x − 4 = 0

Solve for x:

Rewriting:

p

(a) write 7 5×2 y 5 in power notation.

(10)

(11)

3

(b) write (8x) 4 in radical notation.

2

(12)

Simplifying:

(27a12 b15 ) 3 =

(13)

Simplifying:

( 36

)− 2 =

49

(14)

Simplifying:

(15)

Expanding:

1

√

4

(11b)

(12)

(13)

32a31 b18 c4 =

1

(11a)

1

(2x 2 − 5y 2 )2 =

(14)

(15)

√

√

√

7 4 81 − 3 3 64 + 5 3 27 =

(16)

Simplifying:

(17)

Rationalizing the denominator:

(18)

Solve:

(19)

Find the following powers:

√

√ 6√

5+ 2

(16)

=

(17)

8−x=x−2

(18)

(a) i310 =

(19a)

(b) (i12 )2 · i87 =

(19b)

(20)

(a)

Rewrite the following imaginary numbers, using i:

√

−49 =

(b)

√

−180 =

(21)

(−11 + 7i) − (−5i + 4) + (9 − 15i) =

(21)

(22)

2i(5 + 3i)(7 − 9i) =

(22)

(23)

(9 − 5i)2 =

(23)

(24)

3+2i

4−3i

(24)

(25)

2

( i−2

3+i ) =

=

(25)

Math20

Test 3,

100 points

MATH 20

TEST 3

Write your number in the box above.

Due:

Tuesday, 7-28-2020, 11:59 p.m.

Name

(Show necessary work.)

(1)

Let

P (x) = 2×2 − 3x + 7;

(a)

Find P (−5)

(1a)

(b)

Find P (3a − 2)

(1b)

2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =

(2)

Simplifying:

(3)

Multiply:

(4)

Expanding and simplifying:

(4×2 − 5x + 1)(3×2 − 2x − 4) =

(x + 5y)2 − (5x − 3y)2 =

(2)

(3)

(4)

(5)

Factor:

3×5 − 48x =

(5)

(6)

Factor:

5×3 − 20×2 − 105x =

(6)

(7)

Factor:

4×3 − x2 − 36x + 9 =

(7)

(8)

Factor:

27×3 − 64y 3 =

(8)

(9)

Solve for x:

2x(x − 7)(4x + 5)(5x − 8) = 0

(9)

(10)

6×2 + 5x − 4 = 0

Solve for x:

Rewriting:

p

(a) write 7 5×2 y 5 in power notation.

(10)

(11)

3

(b) write (8x) 4 in radical notation.

2

(12)

Simplifying:

(27a12 b15 ) 3 =

(13)

Simplifying:

( 36

)− 2 =

49

(14)

Simplifying:

(15)

Expanding:

1

√

4

(11b)

(12)

(13)

32a31 b18 c4 =

1

(11a)

1

(2x 2 − 5y 2 )2 =

(14)

(15)

√

√

√

7 4 81 − 3 3 64 + 5 3 27 =

(16)

Simplifying:

(17)

Rationalizing the denominator:

(18)

Solve:

(19)

Find the following powers:

√

√ 6√

5+ 2

(16)

=

(17)

8−x=x−2

(18)

(a) i310 =

(19a)

(b) (i12 )2 · i87 =

(19b)

(20)

(a)

Rewrite the following imaginary numbers, using i:

√

−49 =

(b)

√

−180 =

(21)

(−11 + 7i) − (−5i + 4) + (9 − 15i) =

(21)

(22)

2i(5 + 3i)(7 − 9i) =

(22)

(23)

(9 − 5i)2 =

(23)

(24)

3+2i

4−3i

(24)

(25)

2

( i−2

3+i ) =

=

(25)

Math20

Test 3,

100 points

MATH 20

TEST 3

Write your number in the box above.

Due:

Tuesday, 7-28-2020, 11:59 p.m.

Name

(Show necessary work.)

(1)

Let

P (x) = 2×2 − 3x + 7;

(a)

Find P (−5)

(1a)

(b)

Find P (3a − 2)

(1b)

2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =

(2)

Simplifying:

(3)

Multiply:

(4)

Expanding and simplifying:

(4×2 − 5x + 1)(3×2 − 2x − 4) =

(x + 5y)2 − (5x − 3y)2 =

(2)

(3)

(4)

(5)

Factor:

3×5 − 48x =

(5)

(6)

Factor:

5×3 − 20×2 − 105x =

(6)

(7)

Factor:

4×3 − x2 − 36x + 9 =

(7)

(8)

Factor:

27×3 − 64y 3 =

(8)

(9)

Solve for x:

2x(x − 7)(4x + 5)(5x − 8) = 0

(9)

(10)

6×2 + 5x − 4 = 0

Solve for x:

Rewriting:

p

(a) write 7 5×2 y 5 in power notation.

(10)

(11)

3

(b) write (8x) 4 in radical notation.

2

(12)

Simplifying:

(27a12 b15 ) 3 =

(13)

Simplifying:

( 36

)− 2 =

49

(14)

Simplifying:

(15)

Expanding:

1

√

4

(11b)

(12)

(13)

32a31 b18 c4 =

1

(11a)

1

(2x 2 − 5y 2 )2 =

(14)

(15)

√

√

√

7 4 81 − 3 3 64 + 5 3 27 =

(16)

Simplifying:

(17)

Rationalizing the denominator:

(18)

Solve:

(19)

Find the following powers:

√

√ 6√

5+ 2

(16)

=

(17)

8−x=x−2

(18)

(a) i310 =

(19a)

(b) (i12 )2 · i87 =

(19b)

(20)

(a)

Rewrite the following imaginary numbers, using i:

√

−49 =

(b)

√

−180 =

(21)

(−11 + 7i) − (−5i + 4) + (9 − 15i) =

(21)

(22)

2i(5 + 3i)(7 − 9i) =

(22)

(23)

(9 − 5i)2 =

(23)

(24)

3+2i

4−3i

(24)

(25)

2

( i−2

3+i ) =

=

(25)

Math20

Test 3,

100 points

MATH 20

TEST 3

Write your number in the box above.

Due:

Tuesday, 7-28-2020, 11:59 p.m.

Name

(Show necessary work.)

(1)

Let

P (x) = 2×2 − 3x + 7;

(a)

Find P (−5)

(1a)

(b)

Find P (3a − 2)

(1b)

2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =

(2)

Simplifying:

(3)

Multiply:

(4)

Expanding and simplifying:

(4×2 − 5x + 1)(3×2 − 2x − 4) =

(x + 5y)2 − (5x − 3y)2 =

(2)

(3)

(4)

(5)

Factor:

3×5 − 48x =

(5)

(6)

Factor:

5×3 − 20×2 − 105x =

(6)

(7)

Factor:

4×3 − x2 − 36x + 9 =

(7)

(8)

Factor:

27×3 − 64y 3 =

(8)

(9)

Solve for x:

2x(x − 7)(4x + 5)(5x − 8) = 0

(9)

(10)

6×2 + 5x − 4 = 0

Solve for x:

Rewriting:

p

(a) write 7 5×2 y 5 in power notation.

(10)

(11)

3

(b) write (8x) 4 in radical notation.

2

(12)

Simplifying:

(27a12 b15 ) 3 =

(13)

Simplifying:

( 36

)− 2 =

49

(14)

Simplifying:

(15)

Expanding:

1

√

4

(11b)

(12)

(13)

32a31 b18 c4 =

1

(11a)

1

(2x 2 − 5y 2 )2 =

(14)

(15)

√

√

√

7 4 81 − 3 3 64 + 5 3 27 =

(16)

Simplifying:

(17)

Rationalizing the denominator:

(18)

Solve:

(19)

Find the following powers:

√

√ 6√

5+ 2

(16)

=

(17)

8−x=x−2

(18)

(a) i310 =

(19a)

(b) (i12 )2 · i87 =

(19b)

(20)

(a)

Rewrite the following imaginary numbers, using i:

√

−49 =

(b)

√

−180 =

(21)

(−11 + 7i) − (−5i + 4) + (9 − 15i) =

(21)

(22)

2i(5 + 3i)(7 − 9i) =

(22)

(23)

(9 − 5i)2 =

(23)

(24)

3+2i

4−3i

(24)

(25)

2

( i−2

3+i ) =

=

(25)

Math20

Test 3,

100 points

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