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Question 9

<
>

50/1 pt 52 99 0 Details

A radioactive substance decays exponentially. A scientist

begins with 140 milligrams of a radioactive substance. After

28 hours, 70 mg of the substance remains. How many

milligrams will remain after 43 hours?

mg

Give your answer accurate to at least one decimal place

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Question 8

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50/1 pt 52 99 0 Details

the points ( – 1, )

(

Find a formula for the exponential function passing through

3

and (1,12)

f(x) =

=

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Question 11

<
>

B0/1 pt 52 99 0 Details

A car was valued at $45,000 in the year 1991. The value

depreciated to $15,000 by the year 2000.

A) What was the annual rate of change between 1991 and

2000?

Round the rate of decrease to 4 decimal places.

r =

B) What is the correct answer to part A written in

percentage form?

%.

r =

C) Assume that the car value continues to drop by the same

percentage. What will the value be in the year 2003 ?

value = $

Round to the nearest 50 dollars.

=

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Question 10

く

>

50/1 pt 52 99 0 Details

A house was valued at $95,000 in the year 1994. The value

appreciated to $165,000 by the year 2005.

A) What was the annual growth rate between 1994 and

2005?

Round the growth rate to 4 decimal places.

r =

B) What is the correct answer to part A written in

percentage form?

%.

r =

C) Assume that the house value continues to grow by the

same percentage. What will the value equal in the year

2009 ?

value = $

Round to the nearest thousand dollars.

=

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Question 12

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50/1 pt 52 99 0 Details

If 6000 dollars is invested in a bank account at an interest

rate of 9 per cent per year,

Find the amount in the bank after 12 years if interest is

compounded annually:

Find the amount in the bank after 12 years if interest is

compounded quarterly:

Find the amount in the bank after 12 years if interest is

compounded monthly:

Finally, find the amount in the bank after 12 years if

interest is compounded continuously:

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Try a similar question

A car was valued at $45,000 in the year 1991. T

depreciated to $15,000 by the year 2000.

A) What was the annual rate of change between

2000?

0.1294 x 09 -0.1149 Round the rate of deci

decimal places.

r =

B) What is the correct answer to part A written

percentage form?

p= 12.94

x 00 -11.49 %.

C) Assume that the car value continues to drop

percentage. What will the value be in the year

value = $ 8550 x 00 10,400 Round to the ned

dollars.

Х

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Section 4.1

Score: 6/15 6/15 answered

Done

合 v0

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Question 10

く

>

50/1 pt 52 99 0 Details

A house was valued at $95,000 in the year 1994. The value

appreciated to $165,000 by the year 2005.

A) What was the annual growth rate between 1994 and

2005?

Round the growth rate to 4 decimal places.

r =

B) What is the correct answer to part A written in

percentage form?

%.

r =

C) Assume that the house value continues to grow by the

same percentage. What will the value equal in the year

2009 ?

value = $

Round to the nearest thousand dollars.

=

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Section 4.1

Done

色 100

:

Score: 6/15

6/15 answered

Question 12

<
>

50/1 pt 52 99 0 Details

If 6000 dollars is invested in a bank account at an interest

rate of 9 per cent per year,

Find the amount in the bank after 12 years if interest is

compounded annually:

Find the amount in the bank after 12 years if interest is

compounded quarterly:

Find the amount in the bank after 12 years if interest is

compounded monthly:

Finally, find the amount in the bank after 12 years if

interest is compounded continuously:

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Submit Question

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