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Linear Algebra and Eigenvalues Questionnaire

Book:

https://math.berkeley.edu/~yonah/files/Linear%20Al…

Section 1.1: Problems 1-5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25-27.

Section 1.2: Problems 1-3, 9, 11, 13, 17, 19, 23-26, 28-31.

Prove Theorem 5 on Page39

Section 1.3: Problems 1, 2, 5, 6, 11, 12, 13, 14, 15, 17, 21, 23, 25.

Section 1.4: Problems 1-6, 9-12, 14-22, 25-26, 29-36.

Section 1.5: Problems 1-5, 7, 9, 11-19, 23-31.

Section 1.7: Problems 1-3, 7, 9, 11, 17, 21, 23-29, 31-40.

Section 2.1: problems 1-12, 15-26 (only the odd-numbered problems)

Section2.2: Problems 1-5, 7, 8, 11, 13, 15, 17, 18, 29-33.

Section 2.3: Problems 1, 3, 5, 7, 15, 17, 19, 21-24, 26-28.

Section 2.8: Problems 5, 7, 8, 11, 13, 15, 19, 20, 23-25, 27-36

Section 2.9: Problems 1, 3, 5, 9, 19-26

Section 3.1: Problems 1, 3, 5, 7, 9, 11.

Section 3.2: problems 1, 3, 5, 7, 9, 15, 17, 19, 21, 23, 25, 28, 31, 33, 35, 37, 39, 41, 43

Section 5.1: Problems 1, 3, 5, 8, 13, 15, 23-27,

Section 5.3: Problems 1, 2, 5, 6, 7, 15, 21, 23-32

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and
v
Ih
w
are
1
2
solution to the system
b
Av
Lin
berm
awes
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vew
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ru
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T
b
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t
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solutions
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b
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the relationship between
and
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15
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ta
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b
the
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Ax
b
Ax
t
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a
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Question
Under
hom
zero
what conditions
a
Dy the
system has
on
solution
ay
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3 A 44 Az
s
0
x
no
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F’solution to
cola
Avo
is
Since the third column A
a doc
of the first and second
columns A Az the AX 0
has a
Therefore
non
zero
has infinitely
it
solutions
solution
many
0
4,3
Etitt
I
Say
a
non
we
know
that
solution
zero
E
Axe
to
meaning
Lai
I
has
one
the entries is
qq.to
of
non
zero
IA
Iz Az
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Az Az
9 A
G A
Iu Au
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T
es
Az
Atf
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e
Ax
o
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a
then
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columns of A
is
non
a
d
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zero solution iff
columns
other
of A
columns
is
a
of A
has
one
zero
of the
one
the rest
Conclusion
G Ay
Azt
c
of
a
non
of the
doc of the
Axe has only the
getrolution eff none of its
columns is not a d c of the rest
Conclusion
Definition
Let
that
Tesay
dependent if
Vi Vas
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ra
one
Vk
he
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linearly
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4
44
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it
4
k
Examf Determine
483
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are
d
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L
i
solution
We want to
is a doc
we Pearned
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know
of the
that
of
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one
rest
one
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system
a
1
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Y
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E
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LIFE
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Bryn
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1
13
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At
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IBM
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c
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B
b
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C
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c
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de
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e
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re A
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u
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T
416
E 26
38
1.1
1
E
1
6
u
E
u
Let
Teared
A
be
an
and let B and
for which the following
matrix
product
I
defined
are
ACB C
CAB
A CBT C
23
3
CBTC
4
r
A
AB
CAB
In A
In
TAC
B A TCA
B
scalar
A
r as a
5
C
A
AIn
18
identity matrix
man
matrices
sum
and
C
A
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L
IA
9
38
38
AI
383
9
38
Warnings
1
In
2
AB
3
AB
general
AC
o
BA
AB
A
B
C
0
or
Bo
D
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A
At
Transpose
A1
Symmetric
matrices
ATBT
CAB
CABS
B’AT
be
Theorems Let A and B
are appropriate
matrices whose sizes
for the following sums and products
AT
A
CATBF
AT TBT
GAF
r
CAB
r
es
AT
a
scalar
B’AT
Ax
at the solution
Let’s look
u
is
v
u
Hence
we
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a
solution
n
n
say
Au
o
Ar
o
It
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solution
also a
that the solution
is
utv
set
closed
underaddilinfectors
set of
u
ru
we
of
as
a
Cr is
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solution
a
scalar
Au
O
Afra
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Fo
say that feel solutin
is
closed
Ax 0
underscalar
O
o
o
set
flication
b
AX
b
this system
0
not closed
is
under
addition and scalar multiplication
Definition
the solution set of
system A
homogeneous
is
we
write
Ipa
there
X
O
A
NACA
F
Are
a
other
sets
that
are
closed under addition and
scalar multiplication
I
a
closed under addition
in
205
a
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s
5
z
VI
85
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es
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t
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R
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e
f
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buy tbs 43
t
bill
Z
Uz
Ui
a
tabby
the
S
vectors in R
set
of
any
Span of
is closed under addition and
scalar multiplication
Let A
be
any
Span of the columns
Is
span
is
matrix
men
of
called
A
column spance
Ins
Iad
not closed
under
scalar
multiplication
coed
closed
s
Not
under
or
addition
mash
scalar
Nu PCA
CoP A
Span
uh
ai
a
he
ER
e
r
305
Definition A mug of R
called a subspace of R
it is closed ater addition
and
scalar multiplication
is
if
Conclusion
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zero
ace
vector
If
a
subset
of
R
then
in
is
stis
the
S
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a
subspace
of R2
because
it
does not include
the zero
Ax
AO
b
b
b
o
vector
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solution set of Axes
of
it is In a subspace
Hand
of R
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b
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b
be
can
GPA
we
I I
find scalars Xi
L
n
the system Ax b
solution then yes
If
a
if
the
then
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system
To
Null
b
bear
a incortisten
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Nalla
find
solve
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has
GPA
b
Find
tax
A
x
0
we
need to
Y
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t
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342
p
I
IF
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3637
4 3
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a
Null A consists of all the
vectors
in
p of the
where EER
form
15
St
i
benalla
For
Ab
IFL
No
Another
No
befNulla
way
LIFE
O
Linear
APgebra
Linear equation
32
non
32449
7
44
linear equation
sense
3K
KATY
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coefficients
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3
I
22
x
22
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0
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attainastiansen
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8
7
b
7
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32
t
G
32
7
X
73
t a
any
has
no
number
4t
Gt
É
ant
a
ay
O
solution
Linear equation
System of linear equations linear
system
Solution set
coefficients
equivalent system are systems
that have the same solution set
22
ya
47
39
129
1
se
222
1
se
322
3
42
3122
69 8
69 3
X2
a
5
sat
se
Gien
multiplied
2
3
222
K
by
1
No
22
102,41
22,43
solution
I
I
3
d Ilk
solution
No
the solution set is empty
a
21
222
1
222
10
infinitely
of
many
solutions
observation
Geometric
system of linear equations
A
1
has
2
exactly
no
one
22
f
0
8
823
s E 4
solution
many solution
infinitely
3
8
2
222
823
1022
1023
f
222
222
5
8
E3
melt
a
2
solution
8
10
I
Eat E3
23
0
823
3023
8
1
30
0
it
5 EatE3
2
I
0
2
8
8
0
30
3
I
se
y
K
Io
É
E3
222423
a
23
EEZ
ans
0
1
flight
a
1
off
3
4
the system has
a
matrix
entries
a
row S
n
columns
of
a
matrix
en
en
e
a
a
a
coefficient matrix
Augmented matrix
size of
a
matrix
example
J
cofficient matrix is 32 3
Augmented matrix
d
by
92
get
are theft Cat dz
93kt by C Z d
Replacement Replace
II
represents
a
plane
ee
en
Operations applied
size
Elementary operation
one
row
by
the
of itself and a
multiple of another row
sum
interchaning two
Interchange
scaling
multiplying
a
THESE
DO
number
ELEMENTRY
NOT
CHANGE
one
row
rows
by
different from zero
OPERATIONS
THE SOLUTION
SET
the operation keep the systems
equivalent
A system
that has
called
consistent
A
a
a
solution
system
system that does not
solution
is
is
called
have
inconsistent system
Questions
Given
a
Is
If
have
linear system
the system consistent
yes
a
does the system
unique
solution
Exampf Determine of the following
system
is
consistent
222
23
0
222
823
8
2
see
5
10
3
found that this system es
We
consistent
es
AP so
a
23
I
22
0
se
A
we
found that
unique solution
solo
1
11
a
has
a
Determine
in
consistent
of the
following
system
423 8
32 223 1
22
22
822 1223 1
42
I
I
2
3
2
2
3
ii I
I
1
0
I
2
4
88 9
24
8
1
f
kitted
e
OH
the system
we
have
solution
a leading
number in
is
022 023
INCONSISTENT
been
applying
process
efyÉ
a
row
that
is
t
a
called
non
zero
15
1
is
chelon form
form
the
matrix
A
Definition
ray e halon
it has
in
if
following properties
All the
any
non
zero
rows
are
above
K
zerwae
2
Each
entry of
leading
a column
it
3
All
the
below
in
leading
zeros
2
entry
entries
a
column
entry are
a
1
t
I
row
to the right of W
of the row
is in
the Pending
above
a
1
echelon form
Me
c
G
Reduced rechelon form Crreff
a
ref form if
A matrix
it
is in echelon form and
4
the leading entries
5
All the entries in
leading
a
are
are
a
all
column
zeros
I
I
To
0
3
0
I
0
0
08020
0
0
0
o
o
ref
food
o
o
o
d
5 6
i
s
above
Theorem
determine if a system is consistent
reduce it If at any stage
get
chelon form where a row looks like
To
row
an
o
o
to
o
thesystemisinconsistent
leading entry
then
I
ÉÉÉ
Either
column
p
ending entry
entry in a matrix that
at the same position
corresponds
pivot
to
is an
leading entry
a
in
an
chelon
form of the matrix
A
a
X
column
with a pivot is
pivotcolumn
Xz
Xz Xu
as
called
H
Az
I
Trm
Xy
2 ox
q
1
I
0
o
o
x
2 I
34
x
05
Ux
r
7.5
12.5
3
I
I
t 8Xy
V
2
iii
D
in
Xu
D
Xz
X
leading
r
e
ref
pivot
pivot column
IF
sees
i
is
I
see
varia
0
3
a
a
se
se
24
I
t
21
2t
2r
7
3
Er
t
Gt
3 t
2 r
t
18
30
18
4 r
25
Ir
tax
3
3 t
3 t
3
g
1ÉFFEY
P
r
t
t
4
1
11
11
Eam
parametric form
infinitely manysolution
vector form
Parametric form
o
basis
free
variable
variable
o
of
theorem
A
at
not
A
linear system
a
row
o
I
the
o
consistent off
system does
of the form
echelon form of
have
a
the
nightmost column of
D
to
o
the augmented
Eto
Linear
system
Inconsistent
Consister
a
free variables
infinitely
many
No
free
variable
d
unique
solution
solutions
theorem
A
linear system either
has
solution infinitely many
solution or any one solution
no
Determinants
d
a set
a
da t
d
by
of f
b
1
f
t ae
db t
db
I dat
e
y
957 1,11
af
determinant of A
d etCA
IA I
C
f
ease t bdoe
ee t b f
f eat b d
ee t b f
It
E
5
A
I Al
data
1 Alto
0
tae
d e t af
ae
by
51
coefficien matrix
dst
a set
se
1
aft
de
y
de
Y
e
C
by
ey
a e
11
bd
y
9 2 t b 22 t
azz
932
t
k
t
Czse
anti
a
d
it
bz
3
d
Goes da
bye
t b
923
c
dz
t
dat
IFI
eat
I
b
EX
1
C 1 C2
4 O
5
2
0
1dg
lol I
Mitt
IIE
e
C1
2
to
2.627 4.2
2
data
EÉI
E
2
É
I
ax
a
Htt
We can compute the determinant of a
squarematria cross any row and along
any column
EID
ÉÉH
I
j
2 O
E
sit I
41
4
0
T
o
I
I
L
9
1
1
1
2
L
ii
tatted
9
far Ian
9
92
an
theorem the determinant of a
diagonal matrix is the product
of the entries on the main diagonal
of the matrix
A
L
data
1 3 C
5
15
Theorem
the
determinant of
upper triangular
or
an
lower
matrix as the product
of the entries on the main diagonal
triangular
FEET
8
deta
7 t.lu
det 13
73 18.14
L
1
U
Z
H
date
detB deta
d etc
1
0
I
03
3
upper
I

det B
D
L
0.2
2
triangular
6 57.3
15
Theorend Let
1
If
B
is
adding
a
A
be
a
obtained from A
multiple of
then
another row
matrix
square
row
by
column
to
detBideta
2
B is obtained from A by
rows
then
interchanging two columns
If
data
detB
3
If
B
is
multiplying
hunter
r
obtained from A
row
by
thalamus
one
detBerdeta
a
by
non
zero
Ann
upper triangular
Edette
deta
data
tefft
dette
to
O
Unn
Un Un
is
A
TITTA be
A
a
and
O
invertible
square matrix
invertible
TITTA
Then
a
Es
B
detCAB
iff
be
nen
data
detato
matrices
dB
Review
we
we
define
dot
this
use
define dot
We
stated
between
of
2
matrix
2
definition
of
men
to
matrix
the relationship
the dot of
a
matrix and the determinant
of a matrix that obtained
from it by elementary operations
on
row
columns
compute det
any column and across
We
Al
can
0
off
dat CAB
A
along
any row
invertible
data
etB
problem
the redwood forest of California
spotted owl is the main predator of the
wood rate
In
month k
given
Say
the population of the owls
en
Ii
en
rats
w
a
e
Ia
la
Ta
Lk
5
t a 4
Go 10474
as
l
as
Tk
T
C 17Th
Find the evolution of the population
of the owls and rats is the redwood forest
E T in
x
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f
IED
Name: __________________
Last
First
UCSD ID #:____________________
Math 18 Summer 2021
2 hours
1. No materials and calculators are allowed during the exam.
2. Write your solutions clearly and (a) Indicate the number and letter of each question; (b) Present your answers in the same order they appear in
the exam; (c) Start each question on a new page.
3. Show all your work; no credit will be given for unsupported answers.
4. Your answers must be based on the material presented in class; no credit will be given otherwise.
5. We reserve the right to examine you in person on your answers to the problems in this exam.
1 0 1 


1
1. Let A  0 1 0 Show that A is diagonalizable, and write it as A  PP . Find P and the diagonal matrix  . You do


1 0 1 
1
not need to find P . (15 Points)
2.
a. Construct a
3  3 matrix that is invertible but not diagonalizable. (10 Points)
b. Construct a non-diagonal
3  3 matrix that is diagonalizable but not invertible. (5 Points)
3. Let A be diagonalizable. Prove that the determinant of A is equal to the product of its eigenvalues. (10 Points)
4.
a. Construct a
Points)
3  3 matrix A with no zero entry and a vector b  0 in R 3 such that b is not in the column space of A . (10
1
 
b. Construct a 3  3 matrix A with no zero entry such that the vector b  1 is in NulA . (10 Points)
 
1
 4 5 9 2 


5. Let A  6 5 1 12 . An echelon form of A is the matrix


 3 4 8 3
a. Find a basis for
1 2 6 5
0 1 5 6  .


0 0 0 0 
ColA (5 Points)
b. Find a basis for NulA (10 Points)
6.
3
 1 2 3




a. Find the orthogonal projection of b  1 onto the column space of A  1 4 3 (15 Points)
 


 5 
 1 2 3
b. Find all the least square solutions of
Ax  b . (10 Points)
Problems 1-8 (Note u-v=ufv = vt u)

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