Home Β» Nightingale College Mixed Integer Programing Worksheet

Nightingale College Mixed Integer Programing Worksheet

Mixed integer programing:Use math solver program To solve this model a reduced example has been considered because of the
large number of constraints
Jobs
Machine/jobs
1
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M1
17
15
17
14
12
M2
21
22
13
19
20
M3
14
15
13
19
18
π‘šβˆ’1 𝑛
π‘›βˆ’1
π‘šπ‘–π‘› ( βˆ‘ βˆ‘ π‘₯𝑗1 𝑃𝑖𝑗 + βˆ‘ πΌπ‘šπ‘— )
𝑖=1 𝑗=1
𝑗=1
𝑀𝑖𝑛 17𝑋11 + 15𝑋21 + 17𝑋31 + 14𝑋41 + 12𝑋51 + 21𝑋11 + 22𝑋21 + 13𝑋31 + 19𝑋41 + 20𝑋51
+ 14𝑋11 + 15𝑋21 + 13𝑋31 + 19𝑋41 + 18𝑋51
= 𝑀𝑖𝑛 53𝑋11 + 54𝑋21 + 46𝑋31 + 56𝑋41 + 55𝑋51
𝑛
βˆ‘ π‘₯π‘—π‘˜ = 1 , π‘˜ = 1, … ,5
𝑗=1
π‘₯11 +π‘₯21 +π‘₯31 +π‘₯41 + π‘₯51 = 1
π‘₯12 +π‘₯22 +π‘₯32 +π‘₯42 + π‘₯52 = 1
π‘₯13 +π‘₯23 +π‘₯33 +π‘₯43 + π‘₯53 = 1
π‘₯14 +π‘₯24 +π‘₯34 +π‘₯44 + π‘₯54 = 1
π‘₯15 +π‘₯25 +π‘₯35 +π‘₯45 + π‘₯55 = 1
𝑛
βˆ‘ π‘₯π‘—π‘˜ = 1 , 𝑗 = 1, … , 𝑛
π‘˜=1
π‘₯11 +π‘₯12 +π‘₯13 +π‘₯14 + π‘₯15 = 1
π‘₯21 +π‘₯22 +π‘₯23 +π‘₯24 + π‘₯25 = 1
π‘₯31 +π‘₯32 +π‘₯33 +π‘₯34 + π‘₯35 = 1
π‘₯41 +π‘₯42 +π‘₯43 +π‘₯44 + π‘₯55 = 1
π‘₯51 +π‘₯52 +π‘₯53 +π‘₯54 + π‘₯55 = 1
𝑛
𝑛
πΌπ‘–π‘˜ + βˆ‘ π‘₯𝑗,π‘˜+1 𝑃𝑖𝑗 + π‘Šπ‘–,π‘˜+1 βˆ’ π‘Šπ‘–π‘˜ βˆ’ βˆ‘ π‘₯𝑗,π‘˜ 𝑃𝑖+1,𝑗 βˆ’ 𝐼𝑖+1,π‘˜ = 0 π‘“π‘œπ‘Ÿπ‘˜ = 1, . . ,4; 𝑖 = 1, … ,2
𝑗=1
𝑗=1
k= 1, i=1
𝐼11 + 17 βˆ— π‘₯12 + 15 βˆ— π‘₯22 + 17 βˆ— π‘₯32 + 14 βˆ— π‘₯42 + 12 βˆ— π‘₯52 + π‘Š12 βˆ’ π‘Š11
βˆ’ 21 βˆ— π‘₯11 βˆ’22 βˆ— π‘₯21 βˆ’13 βˆ— π‘₯31 βˆ’19 βˆ— π‘₯41 βˆ’20 βˆ— π‘₯51 + βˆ’πΌ21 = 0
For k=1, i=2
𝐼21 + 21 βˆ— π‘₯12 + 22 βˆ— π‘₯22 + 13 βˆ— π‘₯32 + 19 βˆ— π‘₯42 + 20 βˆ— π‘₯52 + π‘Š22 βˆ’ π‘Š21
βˆ’ 14 βˆ— π‘₯11 βˆ’15 βˆ— π‘₯21 βˆ’13 βˆ— π‘₯31 βˆ’19 βˆ— π‘₯41 βˆ’18 βˆ— π‘₯51 βˆ’ 𝐼31 = 0
For k=2 , i=1
𝐼12 + 17 βˆ— π‘₯13 + 15 βˆ— π‘₯23 + 17 βˆ— π‘₯33 + 14 βˆ— π‘₯43 + 12 βˆ— π‘₯53 + π‘Š13 βˆ’ π‘Š12 βˆ’ 21 βˆ— π‘₯12 βˆ’ 22 βˆ— π‘₯22 βˆ’ 13
βˆ— π‘₯32 βˆ’ 19 βˆ— π‘₯42 βˆ’ 20 βˆ— π‘₯52 βˆ’ 𝐼22 = 0
For k=2 , i=2
𝐼22 + 21 βˆ— π‘₯13 + 22 βˆ— π‘₯23 + 13 βˆ— π‘₯33 + 19 βˆ— π‘₯43 + 20 βˆ— π‘₯53 + π‘Š23 βˆ’ π‘Š22 βˆ’ 14 βˆ— π‘₯12 βˆ’ 15 βˆ— π‘₯22 βˆ’ 13
βˆ— π‘₯32 βˆ’ 19 βˆ— π‘₯42 βˆ’ 18 βˆ— π‘₯52 βˆ’ 𝐼32 = 0
For k=3 , i=1
𝐼13 + 17 βˆ— π‘₯14 + 15 βˆ— π‘₯24 + 17 βˆ— π‘₯34 + 14 βˆ— π‘₯44 + 12 βˆ— π‘₯54 + π‘Š14 βˆ’ π‘Š13 βˆ’ 21 βˆ— π‘₯13 βˆ’ 22 βˆ— π‘₯23 βˆ’ 13
βˆ— π‘₯33 βˆ’ 19 βˆ— π‘₯43 βˆ’ 20 βˆ— π‘₯53 βˆ’ 𝐼23 = 0
For k=3 , i=2
𝐼23 + 21 βˆ— π‘₯14 + 22 βˆ— π‘₯24 + 13 βˆ— π‘₯34 + 19 βˆ— π‘₯44 + 20 βˆ— π‘₯54 + π‘Š24 βˆ’ π‘Š23 βˆ’ 14 βˆ— π‘₯13 βˆ’ 15 βˆ— π‘₯23 βˆ’ 13
βˆ— π‘₯33 βˆ’ 19 βˆ— π‘₯43 βˆ’ 18 βˆ— π‘₯53 βˆ’ 𝐼33 = 0
For k=4 , i=1
𝐼14 + 17 βˆ— π‘₯15 + 15 βˆ— π‘₯25 + 17 βˆ— π‘₯35 + 14 βˆ— π‘₯45 + 12 βˆ— π‘₯55 + π‘Š15 βˆ’ π‘Š14 βˆ’ 21 βˆ— π‘₯14 βˆ’ 22 βˆ— π‘₯24 βˆ’ 13
βˆ— π‘₯34 βˆ’ 19 βˆ— π‘₯44 βˆ’ 20 βˆ— π‘₯54 βˆ’ 𝐼24 = 0
For k=4 , i=2
𝐼24 + 1 βˆ— π‘₯15 + 22 βˆ— π‘₯25 + 13 βˆ— π‘₯33 + 19 βˆ— π‘₯43 + 20 βˆ— π‘₯56 + π‘Š24 βˆ’ π‘Š24 βˆ’ 14 βˆ— π‘₯14 βˆ’ 15 βˆ— π‘₯24 βˆ’ 13
βˆ— π‘₯34 βˆ’ 19 βˆ— π‘₯44 βˆ’ 18 βˆ— π‘₯54 βˆ’ 𝐼34 = 0
π‘Š11 = 0 , 𝑖 = 1, … , π‘š βˆ’ 1
π‘Š21 = 0
𝐼1π‘˜ = 0 ; π‘˜ = 1, … , 𝑛 βˆ’ 1
𝐼11 = 0
𝐼12 = 0
𝐼13 = 0
𝐼14 = 0

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