E is a volcano. During a recent eruption, the volcano spewed copious amounts of ash. One small piece of ash was ejected from the volcano with an initial velocity of 368 ft/sec. The height H, in feet, of our ash projectile is given by the equation:
H = -16t^2 + 368t,
Where t is the time in seconds. The graph of this equation will be a parabola. We will assume that the volcano has no height. In other words, when H=0 at t=0.
Question 1. When does the ash projectile reach the its maximum height? t=?
Question 2. What is its maximum height?
Question 3. When does the ash projectile return to the ground?
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I= -16t +368t
Vhere t is the time, in seconds.
We will assum
volcano has no
i.e. H= 0 att
-0, H=0
.when does the ash projectile reach it’s maximum height?
. What is its maximum height?
.when does ash projectile return to the ground?
how transcribed image text
ve will assume that the volcano has no height. i.e. Ho att
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